Dear list,
I'm trying to use total -p to multiply two rows of data like this:
$ echo -e "0 1 2 3\n2 3 4 5"
0 1 2 3
2 3 4 5
$ echo -e "0 1 2 3\n2 3 4 5" |total -p
2 3 8 15
I would expect 0 * 2 = 0 in the first column. Does the -p option not like zeroes? A straight-forward sum gives the expected result:
$ echo -e "0 1 2 3\n2 3 4 5" |total
2 4 6 8
Regards
Axel
Hi Axel,
This is really a bug. Total computes products by converting to a log domain, which of course doesn't work for zero. I can fix this problem, and will do so in the next release.
Cheers for pointing it out.
-Greg
P.S. The reason for converting to log is that it allows geometric means to be computed for almost any set of numbers, which would overflow a straight product.
From: Axel Jacobs <jacobs.axel@gmail.com>
Date: January 29, 2010 8:51:49 AM PSTDear list,
I'm trying to use total -p to multiply two rows of data like this:
$ echo -e "0 1 2 3\n2 3 4 5"
0 1 2 3
2 3 4 5$ echo -e "0 1 2 3\n2 3 4 5" |total -p
2 3 8 15I would expect 0 * 2 = 0 in the first column. Does the -p option not like zeroes? A straight-forward sum gives the expected result:
$ echo -e "0 1 2 3\n2 3 4 5" |total
2 4 6 8Regards
Axel