Dear all,
The man page for rcalc says "By default, tabs and spaces are ignored except
as field separators". I wonder if there is a way to overrule this default
behavior. For example:
echo 1,2,3 4,5 | rcalc -t, -e '$1=if($2-$1,$3,0)' gives '3' as result. Can
it be forced to give '3 4'?
In this case the space is not a field separator, but it causes the rest of
the field be missing from the ouput.
Many thanks,
Victor Lopez-Rioboo Gil
Hi Victor,
I am not sure there is a way to do what you are asking with rcalc. You can use input fields rather than separators with an input format, e.g.:
rcalc -i '${n1},${n2},$(s3),${n4}'
This loads the first two comma-separated values as numbers, the third as a string, and the fourth as a number again. (This is the difference between using curly braces and parentheses in rcalc format fields.) However, there is not much you can do with string fields other than repeat them in the output. They cannot be the arguments or results of any expressions or formulas. Generally, they are simply used as place-holders or a means to repeat the input in the output using a similarly constructed output format (-o option).
You could use the "cond" variable to decide whether to output a record or not in your example, like so:
rcalc -i '${n1},${n2},$(s3),${n4}' -e 'cond=n2-n1' -o '$(s3)'
This would only output the third field when the second is greater than the first. It would not output "0" otherwise, but no line at all.
I don't know if this helps.
-Greg
From: Victor LRG <[email protected]>
Date: June 6, 2017 7:02:59 AM PDTDear all,
The man page for rcalc says "By default, tabs and spaces are ignored except as field separators". I wonder if there is a way to overrule this default behavior. For example:
echo 1,2,3 4,5 | rcalc -t, -e '$1=if($2-$1,$3,0)' gives '3' as result. Can it be forced to give '3 4'?
In this case the space is not a field separator, but it causes the rest of the field be missing from the ouput.
Many thanks,
Victor Lopez-Rioboo Gil
Hi Victor,
If you are using linux or mac, this sort of thing is simple with awk. There
might be an equivalent with windows.
echo 1,2,3 4,5 | awk -F, '{if($2>$1)print $3;else print 0}'
output:
3 4
Andy
On Tue, Jun 6, 2017 at 7:49 AM, Greg Ward <[email protected]> wrote:
Hi Victor,
I am not sure there is a way to do what you are asking with rcalc. You
can use input fields rather than separators with an input format, e.g.:rcalc -i '${n1},${n2},$(s3),${n4}'
This loads the first two comma-separated values as numbers, the third as a
string, and the fourth as a number again. (This is the difference between
using curly braces and parentheses in rcalc format fields.) However, there
is not much you can do with string fields other than repeat them in the
output. They cannot be the arguments or results of any expressions or
formulas. Generally, they are simply used as place-holders or a means to
repeat the input in the output using a similarly constructed output format
(-o option).You could use the "cond" variable to decide whether to output a record or
not in your example, like so:rcalc -i '${n1},${n2},$(s3),${n4}' -e 'cond=n2-n1' -o '$(s3)'
This would only output the third field when the second is greater than the
first. It would not output "0" otherwise, but no line at all.I don't know if this helps.
-Greg
*From: *Victor LRG <[email protected]>
*Date: *June 6, 2017 7:02:59 AM PDT
Dear all,
The man page for rcalc says "By default, tabs and spaces are ignored
except as field separators". I wonder if there is a way to overrule this
default behavior. For example:echo 1,2,3 4,5 | rcalc -t, -e '$1=if($2-$1,$3,0)' gives '3' as result. Can
it be forced to give '3 4'?In this case the space is not a field separator, but it causes the rest of
the field be missing from the ouput.Many thanks,
Victor Lopez-Rioboo Gil
_______________________________________________
Radiance-general mailing list
[email protected]
https://www.radiance-online.org/mailman/listinfo/radiance-general