Hi Marina,
The tn formula assumes your Tn values are between 0 and 1, not 0 and 100% -- your results should be:
void glass smpl_01
0
3 0.4449 0.5248 0.4675
Good that you checked!
-Greg
···
From: marina aviles olmos <[email protected]>
Date: March 17, 2009 9:02:44 AM PDTHi Greg,
I don't know how I didn't thought about this. It seems also like quite
an intuituve description!
The results also look like right.Nevertheless I define how I have proceeded, because there is a step that
could be wrong.From the hole transmitance spectrum of each glass sample I have just
taken the transmittance values at this wavelengths you said and then
calculated its tn#glass sample 01
Rot=700nm Tn=40.8 rtn= 18.093
Green=546 Tn=48.13 gtn= 18.813
Blue=436 Tn=42.87 btn= 18.317void glass smpl_01
0
3 0.18093 0.18813 0.18317And this would be the hole material description of this transparent
glass, als just one layer glass, 10mm thickThanks again,
Marina