Lux-values for points in a plane

Dear user group,

Yet another hurtle in my adventure through Radiance :slight_smile:

I am trying to determine the LT-value (LightTransmission-value) for a pane with external shading. The first step is to calculate the LT-value correctly without external shading. I failed on that :slight_smile:

I followed the steps described in the "Basic Radiance Tutorial" by Axel Jakobs. Here is the data i used.

Coordinates in IllumKoordinater.pts

6.216 0.00 1.8 0 -1 0 (window)
6.216 0.05 1.8 0 -1 0 (black wall located 0.05 m behind the window - in fact all walls are black)

The Window (LT=0,72):
void glass window_glass
0
0
3 .78 .78 .78

cat IllumKoordinater.pts | rtrace -I -ab 4 -h -w -oov kontor.oct | rcalc -e '$1=$2;$2=179*(.265*$4+.670*$5+.065*$6)' > lux.dat

Output
-1 4883.69
-0.95 3049.70

Two things worth noticing here. The output coordinates are not listed correctly which gives me the suspicion that lux-values are is not calculated for the correct coordinates. Furthermore the ratio between the output are not according to the entered LT-value for the window (0,62 vs. 0,72)

Does anyone have an idea of what can be wrong here?

Best regards

Per Hauagaard

路路路

______________________

Per Haugaard,
Griffenfeldsgade 33, 2.tv
2200 K酶benhavn N
Denmark

mobil: +45 26 39 06 40
E-mail: [email protected]
聽聽聽聽聽聽聽
---------------------------------

Tr忙nger du til at se det store billede? Kelkoo giver dig gode tilbud p氓 LCD TV!

6.216 0.00 1.8 0 -1 0 (window)
6.216 0.05 1.8 0 -1 0 (black wall located 0.05 m behind the window - in fact all walls are black)

The Window (LT=0,72):
void glass window_glass
0
3 .78 .78 .78

cat IllumKoordinater.pts | rtrace -I -ab 4 -h -w -oov kontor.oct | rcalc -e '$1=$2;$2=179*(.265*$4+.670*$5+.065*$6)' > lux.dat

Output
-1 4883.69
-0.95 3049.70

If I understand the above correctly you are calculating two points:
one in front of the window, one behind it. The black walls are used
to swallow all light reflections on the inside so you will only have the
transmitted light left.

Two improvements:

1) Move the wall further back or place your second point at ie. 0.04. If
the calculation point coincides with the wall everything is possible.

2) Don't use a box at all. At the perimeter there is a dark horizon (black
walls) which is taken in into the calculation. You could create a sphere
of the material around your calculation point instead.

Two things worth noticing here. The output coordinates are not listed correctly which gives me the suspicion that lux-values are is not calculated for the correct coordinates. Furthermore the ratio between the output are not according to the entered LT-value for the window (0,62 vs. 0,72)

The first is the result of rtrace's interpretation of the '-I' switch (uppercase 'I'!)
rtrace creates a 'virtual surface' at the calculation point and starts the calculation
from the point of the view vector. In your case these are (6.216+0, 0+-1, 1.8+0)
and (6.216+0, 0.05+-1, 1.8+0). Your rcalc command prints only the y-coordinate.

The second problem I can't explane but depending on the size of your
box the 'dark horizon' might have some influence here.

Regards,
Thomas

路路路

On 13 May 2008, at 13:51, Per Haugaard wrote: