Wow, that is exactly what I was looking for. I will modify bsdf2rad in
order to get the Hemispherical transmittance (or reflectance) as the stdout.
So I should do, for every pixel´s incident Theta and Phi I want, the
following:
*bsdf2rad -t TT_bsdf.xml in_Theta in_Phi 2>
hemispherical_transmission.txt*
Thanks, Greg, as usual.
Germán
···
2014-02-17 18:55 GMT-03:00 Greg Ward <[email protected]>:
Hi Germán,
You can compute the total hemispherical transmittance for a particular
incident angle using the bsdf library, which is also reported to the
standard error by bsdf2rad when you run it.Best,
-Greg*From: *CHI-German Molina <[email protected]>
*Date: *February 17, 2014 12:38:49 PM GMT+01:00
Hello Greg, and thanks for your answer.
I did not know of the existence of bsdf2rad, I will try it soon... also,
I think I will forget about interpolating, haha.Is it possible to integrate the outgoing radiation with TT??? My idea is
to just plot DIRECTIONAL transmittance, so people can choose one or another
shading device for their designs. I want to explore the posibility of
overlaying these plots with a solar plot of a certain location, and choose
a device that blocks the Solar Heat Gains when needed.THANKS A LOT
2014-02-14 14:50 GMT-03:00 Greg Ward <[email protected]>:
Hi Germán,
Why not use a tensor tree output of genBSDF in this case? High
resolution on incoming and outgoing angles where it matters is why it was
developed. You can use the C routines to query the TT directly, or use
bsdf2rad to generate a Radiance model for visualization.Cheers,
-Greg*From: *CHI-German Molina <[email protected]>
*Date: *February 14, 2014 8:17:12 AM PST
Hi Lars, Thanks a lot for the quick answer, but I think my question was
not really clear.What I want to achieve is to get the directional transmitance from" any"
angle. Interpolating would allow me getting a continuous (although not
really exact) value. This is mainly for visualization purposes, not really
for getting exact values. By increasing the number of patches I would have
a better resolution, but still I would have "bins" and not a continuous
value.I hope is clear. If it is too hard (i.e. there is not any program that
does it for me), I can just increase the number of bins, and just smooth
the final image.Thanks a lot!
Germán
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