I’m learning Radiance and I need some assurance, that what I understood so far is correct.
I’m trying to recreate 3phase method(Subramaniam), and hoping to get a W/m2 output.
please correct me if I’m wrong(I’ve slightly modifying the procedure hoping to get calculate irradiance on horizontal surface in W/m2)
gendaymtx -m 1 -of -O1 –c 1 1 1 London.wea > London-m1O1.smx
Oconv -f materials.mtl room.rad > room.oct
rfluxmtx -v -I+ -ab 4 -ad 5000 -lw 0.0002 -n 16 -y 28 - objects/GlazingVmtx.rad -i room.oct < points.txt > v.mtx
rfluxmtx -v -ff -ab 4 -ad 1000 -lw 0.001 -c 1000 -n 16 GlazingVmtx.rad skyglow.rad -i room.oct > daylight.dmx
dctimestep v.mtx clear.xml aylight.dmx London-m1O1.smx | rmtxop -fa -t -c 1 1 1 - > results/CLEAR.ill
what I’m interested the most is if my use of
- -O1 and -c 1 1 1 @ gendaymtx would use total solar radiance (W/m2) as gray sky(and if it’s needed);
- if my understanding of the rmtxop -c 1 1 1 would provide me in W/m2 as oposed to Lux value (with -c 47.4 119 11.6)
- is it to expect the result conversion from Lux/W/m2 to be as simple as 1/179?
thank you for reading and any comment